1.

A car travelling at `36 km//h` speeds upto `72 km//h` in `5` seconds. What is its acceleration ? If the same car stops in `20` seconds , what is the acceleration?

Answer» Correct Answer - `2 m//s^(2)` ; `-1 m//s^(2)`
Here, ` u = 36 km//h = 10 m//s , v = 72 km//h = 20m//s , t = 5 s`
`a = ( v - u)/( t) = ( 20 - 10)/(5) = 2 m//s^(2)`
In the second case , `u = 72 km//h = 20 m//s , v = 0 , t = 20s`.
` a = ( v - u) /(t) = ( 0 - 20)/( 20) = - 1 m//s^(2)`


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