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A car travelling with a velocity of 80 km/h slowed down to 44 km/h in 15 s. The retardation isA. `0.67 ms^(-2)`B. `1 ms^(-2)`C. `1.25 ms^(-2)`D. `1.5 ms^(-2)` |
Answer» Correct Answer - A `a=("Chamge in velocity")/("Time taken")=(upsilon_(f)-upsilon_(i))/(t)` ltrgt `=((44xx(5)/(18))-(80xx(5)/(18)))/(15)=-0.67m//s^(2)` Negative sign represents the retardation. |
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