A car weighs 1800 kg. The distance between its front and back axles is 1.8 m. Its centre of gravity is 1.05 m behind the front axle. Determine the force exerted by the level ground on each front and back wheel.

A car weighs 1800 kg. The distance between its front and back axles is

1.	A car weighs 1800 kg. The distance between its front and back axles is 1.8 m. Its centre of gravity is 1.05 m behind the front axle. Determine the force exerted by the level ground on each front and back wheel.
Answer» Solution : For translational equilibrium of CAR `N_(F)+N_(B)=W=1800xx9.8=17640 N` For ROTATIONAL equilibrium of car `105N_(F)=0.75 N_(B)` `105 N_(F)=0.75(1760-N_(F))` `1.8N_(F)=13230` `N_(F)=13230//1.8=7350 N` `N_(B)=17640-7350=10290 N` Force on each front wheel `=(7350)/(2)=3675 N` Force on each back wheel `=(10290)/(2)=5145 N`