A carbon compound A forms B with sodium metal and again A forms C with

1.	A carbon compound A forms B with sodium metal and again A forms C with PCl5, but B and C form diethyl ether. Therefore A, and B and C are :–(a) C2H5OH, C2H5ONa, C2H5Cl(b) C2H5Cl, C2H5ONa, C2H5Cl2(c) C2H5OH, C2H6, C2H5Cl2(d) C2H5OH, C2H5Cl, C2H5ONa
Answer» Correct Option (a) C₂H₅OH, C₂H₅ONa, C₂H₅Cl Explanation: C₂H₅OH(A) + Na → C₂H₅ONa(B) C₂H₅OH(A) + PCl₅ → C₂H₅Cl(C) C₂H₅ONa(B) + C₂H₅Cl (C) → C₂H₅OC₂H₅ + NaCl

A carbon compound A forms B with sodium metal and again A forms C with PCl5, but B and C form diethyl ether. Therefore A, and B and C are :–(a) C2H5OH, C2H5ONa, C2H5Cl(b) C2H5Cl, C2H5ONa, C2H5Cl2(c) C2H5OH, C2H6, C2H5Cl2(d) C2H5OH, C2H5Cl, C2H5ONa

Answer»

Correct Option (a) C₂H₅OH, C₂H₅ONa, C₂H₅Cl

Explanation:

C₂H₅OH(A) + Na → C₂H₅ONa(B)

C₂H₅OH(A) + PCl₅ → C₂H₅Cl(C)

C₂H₅ONa(B) + C₂H₅Cl (C) → C₂H₅OC₂H₅ + NaCl

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A carbon compound A forms B with sodium metal and again A forms C with PCl5, but B and C form diethyl ether. Therefore A, and B and C are :–(a) C2H5OH, C2H5ONa, C2H5Cl(b) C2H5Cl, C2H5ONa, C2H5Cl2(c) C2H5OH, C2H6, C2H5Cl2(d) C2H5OH, C2H5Cl, C2H5ONa

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