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| 1. |
A carnot engine has an efficiency 0.4. When the temperature of the source is increased by 20^(@)C and the sink is reduced by 20^(@)C, its efficiency is found to increase to 0.5. Calculate the temperature of source and sink. |
| Answer» Solution :`0.6 = T _(2) //T_(1) , 0.5 = (T_(2) - 20) T _(1) + 20,` SOLVING `T _(1) = 300 K, T _(2) = 180 K` | |