A carnot engine having an efficiency of (1)/(10) as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is

A carnot engine having an efficiency of (1)/(10) as heat engine, is us

1.	A carnot engine having an efficiency of (1)/(10) as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is
Answer» 90 J 99 J 100 J 1 J Solution :The relation between coefficient of performance and efficiency of carnot engine is GIVEN as `beta = (1- eta)/(eta)` Given `eta = (1)/(10), W= 1 J :. beta = (1-(1)/(10))/((1)/(10)) = (9)/(10).10 = 9` Since, `beta = (Q_(2))/(W)`, where `Q_(2)` is the AMOUNT of energy absorbed from the reservoir `:. Q_(2) = beta W = 9 xx 10 = 90 J`