A Carnot engine is being operated by taking heat from a source at temperature 527^(@)C. If the surrounding temperature is 27^(@)C, what is the efficiency of the engine? If the source supplies heat at the rate of 10^(9)J per minute, how much usable work is obtained per minute?

A Carnot engine is being operated by taking heat from a source at temp

1.	A Carnot engine is being operated by taking heat from a source at temperature 527^(@)C. If the surrounding temperature is 27^(@)C, what is the efficiency of the engine? If the source supplies heat at the rate of 10^(9)J per minute, how much usable work is obtained per minute?
Answer» Solution :Temperature of the source, `T_(1) = 527^(@)C = (527 + 273) K = 800 K` Temperature of the sink, `T_(2) = 27^(@)C = (27+ 273) K = 300 K` So, efficiency `ETA = W/(Q_1)` `:. W = eta Q_(1) = 5/8 xx 10^(9) = 6.25 xx 10^(8) J cdot "min"^(-1)`.