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A Carnot engine of efficiency 40% , takes heat from a source maintained at a temperature of 500 K . If is desired to have an engine of efficiency 60%. Then , the source temperature for the same sink temperature must be

Answer» <html><body><p></p>Solution :`eta=<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>-(T_(2))/(T_(1)),0.4=1-(T_(2))/(500)<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> T_(2)=<a href="https://interviewquestions.tuteehub.com/tag/300k-306432" style="font-weight:bold;" target="_blank" title="Click to know more about 300K">300K</a>` <br/> `0.6=1-(T_(2))/(T_(1)^(1))=1-(<a href="https://interviewquestions.tuteehub.com/tag/300-305868" style="font-weight:bold;" target="_blank" title="Click to know more about 300">300</a>)/(T_(1)^(1))rArr T_(1)^(1)=(300)/(0.4)=<a href="https://interviewquestions.tuteehub.com/tag/750k-1919963" style="font-weight:bold;" target="_blank" title="Click to know more about 750K">750K</a>`</body></html>


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