1.

A carnot engine takes in 3 xx 10^6 cal of heat from source at 627^@ C and gives it to a sink at 27^@ C. The work done by the engine would be _____ (J=4.2 J/cal).

Answer»

zero
`4.2xx10^6` J
`8.4xx10^6` J
`16.8 xx10^6` J

Solution :Temperature of HEAT source `T_1`=273+627=900 K
Temperature of heat sink `T_2`= 273+27 = 300 K
Heat absorbs from source ,
`Q_1=3xx10^6` cal
`=4.2xx3xx10^6` Joule
`rArr` The EFFICIENCY of CARNOT engine,
`eta=1-T_2/T_1`
`=1-300/900`
`=600/900`
`=2/3`
Now efficiency of carnot engine `eta=W/Q_1`
`therefore W=eta Q_1`
`=2/3xx4.2xx3xx10^6`
`=8.4xx10^6` J


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