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A carnot engine takes in 3 xx 10^6 cal of heat from source at 627^@ C and gives it to a sink at 27^@ C. The work done by the engine would be _____ (J=4.2 J/cal). |
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Answer» zero Temperature of heat sink `T_2`= 273+27 = 300 K Heat absorbs from source , `Q_1=3xx10^6` cal `=4.2xx3xx10^6` Joule `rArr` The EFFICIENCY of CARNOT engine, `eta=1-T_2/T_1` `=1-300/900` `=600/900` `=2/3` Now efficiency of carnot engine `eta=W/Q_1` `therefore W=eta Q_1` `=2/3xx4.2xx3xx10^6` `=8.4xx10^6` J |
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