A Carnot engine takes up 200 cal of heat per cycle from a source at temperature 500 K and rejects 150 cal of heat to the sink. What is the temperature of the sink and the efficiency of the engine?

A Carnot engine takes up 200 cal of heat per cycle from a source at te

1.	A Carnot engine takes up 200 cal of heat per cycle from a source at temperature 500 K and rejects 150 cal of heat to the sink. What is the temperature of the sink and the efficiency of the engine?
Answer» SOLUTION :`(Q_1)/(Q_2) = (T_1)/(T_2) or, T_(2) = T_(1) cdot (Q_2)/(Q_1) = 500 xx (150)/(200) = 375 K` EFFICIENCY, `ETA = 1 - (Q_2)/(Q_1)` `=1 - (T_2)/(T_1) = 1 - (375)/(500) = 1 - 3/4 = 1/4` ` = 1/4 xx 100% = 25%`.