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A carnot engine, where efficiency is 40% takes heat from a source maintained at a temperature of 500K. It is have an engine of efficiency60%. Then, the intake temperature for the same exhaust(sink) temperature must be |
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Answer» Solution :`eta=1-T_(2)/T_(1),0.4=1-T_(2)/500` `rArr T_(2)=300K` `0.6=1-T_(2)/T_(1)=1-300/T_(1)^(1)` `rArrT_(1)^(1)=300/0.4=750K` |
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