1.

A carnot engine, where efficiency is 40% takes heat from a source maintained at a temperature of 500K. It is have an engine of efficiency60%. Then, the intake temperature for the same exhaust(sink) temperature must be

Answer»

Solution :`eta=1-T_(2)/T_(1),0.4=1-T_(2)/500`
`rArr T_(2)=300K`
`0.6=1-T_(2)/T_(1)=1-300/T_(1)^(1)`
`rArrT_(1)^(1)=300/0.4=750K`


Discussion

No Comment Found