1.

A cart loaded with sand moves along a horizontal floor due to constant force F, coinciding in direciton with the velocity of cart. In the process the sand spills through a hole in the bottom with a constant rate mu kgs^(-1). If at the initial moment t = 0 the cart with loaded sand has the mass m_(0) and its velocity was equal to zero (beglect friction). Then

Answer»

the acceleration of the cart at time t is `(F)/(m_(0)-mu t)`
the VELOCITY of the cart at time t is `(F)/(mu) ln[(m_(0))/(m_(0) - mu t)]`
the acceleration of the cart at time t is `(F)/(m_(0) + mu t)`
the velocity of the cart at time t is `(F)/(2MU)ln[(m_(0))/(m_(0)-mu t)]`

ANSWER :A::B::C


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