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A catalyst lower the activation energy of a reaction from `200KJ "mol"^(-1)` to `100 KJ "mol"^(-1)`. The temperature at which the rate of uncatalysed reaction will be same as the rate of catalysed reaction at `25^(@)C` is (assuming Arrheneous consant `A` to be same in both the case)A. `50^(@)C`B. `225^(@)C`C. `323^(@)C`D. `596^(@)C` |
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Answer» Correct Answer - C `(E_(a_(1)))/(T_(1))=(E_(a_(2)))/(T_(2))` `200/(T_(1))=100/298` `T_(1)=596K=323^(@)C` |
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