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A cavity of radius b is made in a disc of mass M, radius R, as ahown in fig. Find the new COM- A. `(-b^(2))/(R+b)`B. `(-b^(2))/(R-b)`C. `(-R)/(2R+b)`D. `(-R)/(3R+b)` |
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Answer» Correct Answer - A `x_(CM)=(M(0)-(Mb^(2))/(R^(2))(R-b))/(M-(Mb^(2))/R^(2))` `=-(b^(2))/(R+b)` |
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