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A CE amplifier has a voltage gain 50, an input impedance of 1000 ohm, and an output impendance of 200 ohm. The power gain of the amplifier will beA. 24 dBB. 41 dBC. 250 dBD. 12500 dB |
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Answer» Correct Answer - B Power gain in `dB =10 log.P_(0)/P_(i)=10log .(V_(0)^(2)//R_(0))/(V_(i)^(2)//R_(i))` `=10 log.(V_(0)/V_(i))^(2)xxR_(i)/R_(0) =10 log .(50)^(2)xx1000/200` `=10 log 12500=10xx4.0969~~41 dB` |
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