A cell is set up between copper and silver electrodes as follows: `Cu(s)I Cu^(2+)(aq)II Ag^+(aq)Iag(S)` If the two half cells work under standard conditions, calculate the EMF of the cell `(Given E^(@)_(Cu^(2+)//Cu) =+0.34 V,E^(@)_(Ag^(+)//Ag)" " =+0.80 V)`

A cell is set up between copper and silver electrodes as follows: `Cu(

1.	A cell is set up between copper and silver electrodes as follows: `Cu(s)I Cu^(2+)(aq)II Ag^+(aq)Iag(S)` If the two half cells work under standard conditions, calculate the EMF of the cell `(Given E^(@)_(Cu^(2+)//Cu) =+0.34 V,E^(@)_(Ag^(+)//Ag)" " =+0.80 V)`
Answer» From the `E^(@)` values it is clear that copper acts as the anode silver as the cathode. `E^(@)_(cell)=E^(@)_(cathode-E^(@))_(Enode)=0.80-(0.34)=+0.46 "volt"`

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A cell is set up between copper and silver electrodes as follows: `Cu(s)I Cu^(2+)(aq)II Ag^+(aq)Iag(S)` If the two half cells work under standard conditions, calculate the EMF of the cell `(Given E^(@)_(Cu^(2+)//Cu) =+0.34 V,E^(@)_(Ag^(+)//Ag)" " =+0.80 V)`

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