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A cell of emf. `4.5 V` is connected to a junction diode whose barrier potential is `0.7 V`. If the external resistance in the circuit is `190 Omega`. The current in the circuit isA. `20 mA`B. `2 mA`C. `23 mA`D. `200 mA` |
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Answer» Correct Answer - A `V=4.5-0.7=3.8V, R=190 Omega,i=(V)/(R)`. |
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