1.

A cell of internal resistance r drives a current through an external resistance R. The power delivered by the cell to the external resistance is maximum when (a) R = r (b) R >> r (c) R << r (d) R = 2r

Answer»

Correct Answer is: (a) R = r 

Let  = emf of the cell, i = current in the circuit

i =  / R + r.

Power delivered to R = P = i2R =  2R/(R + r)2 = f(R).

For P to be maximum, dP/dR = 0 = 2 [1 / (R + r)2 - 2R / (R + r)3]

or 2R = R + r 

or R = r



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