A certain block weighs 15 N in air. But it weighs only 12 N completely in another liquid, it weighs 13 N. Calculate the relative density of (i) the block and (ii) the liquid.

A certain block weighs 15 N in air. But it weighs only 12 N completely

1.	A certain block weighs 15 N in air. But it weighs only 12 N completely in another liquid, it weighs 13 N. Calculate the relative density of (i) the block and (ii) the liquid.
Answer» Solution :(i) RELATIVE density of body `=(W_("air"))/(W_("air")-W_("water"))` where `W_("air")=15N` (WEIGHT of the body in air) and `W_("water")=12N` (weight of the body in water) `:.R.D_(B)=(15N)/(15 N-12N)=5` (i) `R.D_(L)=("loss in weight in LIQUID")/("loss in weight in water")=(15-13)/(15-12)=2/3`