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A certain buffer solutions contains equal concentration of `X^(-)` and HX. The `K_(b)` for HX is `10^(-10)`. The pH of the buffer isA. 4B. 7C. 10D. 14 |
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Answer» Correct Answer - A `X^(-) + H_(2)O hArr OH^(-) + HX` `K_(b) = ([OH^(-)][HX])/([X^(-)])` `HX hArr H^(+) + X^(-)` `K_(a) = ([H^(+)][X^(-)])/([HX]), :. K_(a) xx K_(b) = [H^(+)][OH^(-)] = K_(w) = 10^(-14)` Hence `K_(a) = 10^(-4)` Now as `[X^(-)] = [HX], pH = pK_(a) = 4`. |
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