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A certain force acting on a body of mass 10 kg at rest moves it through 125 m in 5 seconds. If the same force acts on a body of mass 15 kg, what is the acceleration produced? |
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Answer» in the case of the first body, u = 0; t = 5 s; s = 125 m Substituting these values in the equation, s = ut + 1/2 at 125 = 0 × 5 + 1/2 × a × (5)2 1/2 × a × 25 ∴ a = (2 x 125/25) = 10 ms-2 F = m × a = 10 × 10 = 100 N If the same force acts on another body of mass 15 kg, the amount of acceleration produced is, a = F/m = 100/15 = 6.67 ms-2. |
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