1.

A certain force acting on a body of mass 10 kg at rest moves it through 125 m in 5 seconds. If the same force acts on a body of mass 15 kg, what is the acceleration produced?

Answer»

in the case of the first body,

u = 0;

t = 5 s;

s = 125 m

Substituting these values in the equation,

s = ut + 1/2 at

125 = 0 × 5 + 1/2 × a × (5)2

1/2 × a × 25

∴ a = (2 x 125/25) = 10 ms-2

F = m × a = 10 × 10 = 100 N

If the same force acts on another body of mass 15 kg, the amount of acceleration produced is,

a = F/m = 100/15

= 6.67 ms-2.



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