InterviewSolution
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InterviewSolution
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A certain gas takes three times as long to effuse out as helium. Its molar mass will beA. `27 u`B. `36 u`C. `64 u`D. `9 u` |
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Answer» Correct Answer - B `(r_(1))/(r_(2))=(V_(1)//t_(1))/(V_(2)//t_(2))=(t_(2))/(t_(1))=sqrt((M_(2))/(M_(1)))` (for equal volumes, `V_(1)=V_(2)`) `implies (M_(2))/(M_(1))=(t_(2)^(2))/(t_(1)^(2))` `implies M_(2)= 4xx(3)^(2)= 36 u` |
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