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A certain quantity of electricity is passed through an aqueous solution of `AgNO_(3)` and cupric salt solution connected in series . The amount of Ag deposited is 1.08 g. then the amount of copper deposited is (At. Mass Cu = 63.5 , Ag = 108) .A. 0.6454 gB. 6.354 gC. 0.3177 gD. 3.177 g |
Answer» Correct Answer - C `("Wt. of Cu")/("Wt. of Ag") = ("Eq. of mass of Cu")/("Eq. mass of Ag")` `("Wt. of Cu")/(1.08) = (63.5//2)/(108)` or Wt. of Cu = `0.3177` g |
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