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A certain substance decays to 1/232 of its initial activity in 25 days. Calculate its half-life. |
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Answer» Fraction of substance decays `= ("Quantity remains")/("Initial quantity")` `=(1)/(2^(n))=(1)/(32)=(1)/(2^(5))` `therefore n = 5` Duration of time = 2 days We know `(n)=("Duration of time")/("Half life time")` `therefore` Half life time `=("Duration of time")/(n)` `(25)/(5)=5` days |
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