1.

A certain volume of Methane diffuses in 10 Sec through a porous partition. The time taken by an equal volume of oxygen to diffuse under the same condition is

Answer»

14.14 Sec. 
7.07 Sec. 
20 sec. 
5 Sec 

Solution :`((DELTAV)/(10))/((DeltaV)/(t_2)) = SQRT(32/16) = sqrt(2)`.
`(t_2)/(10) = 1.414 implies t_2 = 14.14 "sec"`.


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