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A certain volume of Methane diffuses in 10 Sec through a porous partition. The time taken by an equal volume of oxygen to diffuse under the same condition is |
Answer» <html><body><p>14.14 Sec. <br/>7.07 Sec. <br/><a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> sec. <br/>5 Sec <br/></p>Solution :`((<a href="https://interviewquestions.tuteehub.com/tag/deltav-2053504" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAV">DELTAV</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>))/((DeltaV)/(t_2)) = <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(32/16) = sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`. <br/> `(t_2)/(10) = 1.414 implies t_2 = 14.14 "sec"`.</body></html> | |