InterviewSolution
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InterviewSolution
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A certain weak acid has `K_(a)=1.0xx10^(-4)`. Calculate the equilibrium constant for its reaction with a strong base. |
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Answer» `{:(HA,+,BOH,hArr,BA,+,H_(2)O),("weak",,"strong",,,,,):}`:}` or HA+B^(+)+OH^(-) hArr B^(+)+A^(-)+H_(2)O or HA + OH^(-) hArr A^(-)+ H_(2)O` `K=([A^(-)])/([HA][OH^(-)]) ` ...(i) Further, for the weak acid, `HA hArr H^(+)+A^(-), K_(a) = ([H^(+)][A^(-)])/([HA])` ...(ii) Also `K_(w)=[H^(+)][OH^(-)]` ...(iii) From eqns. (i), (ii) and (iii), `K=(K_(a))/(K_(w))=(10^(-4))/(10^(-14))=10^(10)` |
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