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A certain work is completed by A and B together in 10 days. If A had worked at twice the speed and B had worked at half his speed it would have taken them 8 days to finish the work. Find the time in which B can alone finish the work. |
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Answer» 20 days in 10 days. LET the number of days taken by A ALONE be 'a' and by B alone be 'b' In 1 day, A COMPLETES `1//a` part and B completes `1//b` part. `1//a+ 1//b + 1//10 -----(1)` Now, if A had worked at twice the speed and B had worked at half his speed it would have taken them 8 days to finish the work. thus, `2//a + 1//2b=1//8 -----(2)` `2xx(1)- (2)` `rArr 2//b - 1//2b = 1//5 - 1//8` `rArr 3//2b = 3//40` `rArr b = 20` days |
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