1.

A certain work is completed by A and B together in 10 days. If A had worked at twice the speed and B had worked at half his speed it would have taken them 8 days to finish the work. Find the time in which B can alone finish the work.

Answer»

20 days
24 days
30 days
32 days

Solution :Given, A certain work is completed by A and B together
in 10 days.
LET the number of days taken by A ALONE be 'a' and by
B alone be 'b'
In 1 day,
A COMPLETES `1//a` part and B completes `1//b` part.
`1//a+ 1//b + 1//10 -----(1)`
Now, if A had worked at twice the speed and B had
worked at half his speed it would have taken them
8 days to finish the work.
thus, `2//a + 1//2b=1//8 -----(2)`
`2xx(1)- (2)`
`rArr 2//b - 1//2b = 1//5 - 1//8`
`rArr 3//2b = 3//40`
`rArr b = 20` days


Discussion

No Comment Found