A chain of length 1 and mass m lies on the surface of a smooth sphere of radius Rgt1 with one end tied to the top of the space. Suppose the chain is released and slides down the sphere. Find the kinetic energy of the chain, when it has slid through an angle theta.

A chain of length 1 and mass m lies on the surface of a smooth sphere

1.	A chain of length 1 and mass m lies on the surface of a smooth sphere of radius Rgt1 with one end tied to the top of the space. Suppose the chain is released and slides down the sphere. Find the kinetic energy of the chain, when it has slid through an angle theta.
Answer» `(mR^(2)G)/LSIN (L/R)` `(mR^(2)g)/l(SIN(l/R)+sin theta)` `(mR^(2)g)/l(sin(l/R)-sin theta)` `(mR^(2)g)/l(sin(l/R)+sin theta-sin (theta+l/R))` ANSWER :D