1.

A character array B[7] [6] has a base address 1046 at 0, 0. Calculate the address at B[2] [3] if the array is stored Column Major wise. Each character requires tw o bytes of storage.

Answer»

B + W [(I – LBR) + M (J – LBC)] 

= 1046 + 2 [(2 – 0) + 7(3 – 0)] 

= 1046 + 2(2 + 21) 

= 1046 + 2(23)

= 1046 + 46 

= 1092



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