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A charge of +2.0×10−8 C is placed on the positive plate and a charge of −1.0×10−8 C on the negative plate of a parallel-plate capacitor of capacitance 1.2×10−3 μF. Calculate the potential difference developed between the plates. |
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Answer» A charge of +2.0×10−8 C is placed on the positive plate and a charge of −1.0×10−8 C on the negative plate of a parallel-plate capacitor of capacitance 1.2×10−3 μF. Calculate the potential difference developed between the plates. |
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