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A charge of `4xx10^(-9)C` is distributed uniformly over the circumference of a conducting ring of radius 0.3m. Calculate the field intensity at a point on the axis of the ring at 0.4m from its centre, and also at the centre.

Answer» Correct Answer - `115.2 N//C` ; Zero
`q = 4xx10^(-9)C, a = 0.3m, r = 0.4m, E = ?`
`E = (q r)/(4pi in_(0) (r^(2) + a^(2))^(3//2))`
`E = (14.4)/((0.5)^(3)) = 115.2 N//C`
At the center of ring, `r = 0, :. E = 0`


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