InterviewSolution
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InterviewSolution
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A charge of 8.0 mA in the emitter current brings a charge of 7.9 mA in the collector current. The values of `alpha and beta` areA. `0.99, 90`B. `0.96,79`C. `0.97,99`D. `0.99,79` |
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Answer» Correct Answer - D Given that, change in emitter current, `DeltaI_(E)=8mA` and change in collector current, `DeltaI_(C)=7.9mA` We know that, `alpha=(DeltaI_(C))/(DeltaI_(E))impliesalpha=(7.9)/(8)impliesalpha~-0.99` Also we know that `beta=(alpha)/(1-alpha)` `impliesbeta=((7.9)/(8))/(1-(7.9)/(8))=(7.9)/(8-7.9)` or `beta=(7.9)/(0.1)=79` Hence, the required answer is `alpha=0.99andbeta=79` |
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