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A charge `q = -2.0 muC` is placed at origin. Find the electric field at `(3 m, 4 m, 0)`. |
Answer» Correct Answer - A::B::C::D `E=(1/(4piepsilon_0)) (q/r^3)(r_p-r_q)` Here, `r=sqrt((3)^2+(4)^2)=5m` `:. E=((9xx10^9)(-2xx10^-6))/((5)^3)(3hati+4hatj)` `=-(4.32hati+5.76ecj)xx10^2N//C` |
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