A charge q enters in a perpendicular direction of \(\vec B\) with \ – InterviewSolution

1.	A charge q enters in a perpendicular direction of \(\vec B\) with \(\vec V\) velocity. What would be the force on this charge and what would be the path of the particle?
Answer» Force acting on charge F = q \(\overrightarrow{(v} \times \vec{B} )\) \(\|\vec F\|\) = qvBsin 90°= qvB The path of the particle will be circular.

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