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A charge q is placed at the centre of the line joining two equal charges Q. The system of the three charges will be in equilibrium if q is equal to:A. `-4Q`B. `-(Q)/(4)`C. `-(Q)/(2)`D. `+(Q)/(2)` |
Answer» Correct Answer - B For equilibrium, net force on q = 0 `therefore" "(kqQ)/((2x)^(2))+(kqQ)/(x^(2))=0` `therefore" "q=-Q//4` |
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