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A charge q is placed at the centre of the line joining two equal charges Q. The system of the three charges will be in equilibrium if q is equal to:A. `Q//4`B. `-Q//4`C. `-Q//8`D. `Q//8` |
Answer» Correct Answer - B For equilibrium net force must be zero `i.e." "1/(4piin_(0))(Qq)/((r//2)^(2))+1/(4piin_(0))(Q Q)/r^(2)=0` `therefore" "q=(-Q)/4` |
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