A charge `+Q` is uniformly distributed in a spherical volume of radius R. A particle of charge `+q` and mass m projected with velocity `v_0` the surface of the sherical volume to its centre inside a smooth tunnel dug across the sphere. The minimum value of `v_0` such tht it just reaches the centre (assume that thee is no resistance on the particle except electrostatic force) of he sphericle volume isA. `sqrt((Qq)/(2piepsilon_0mR))`B. `sqrt((Qq)/(piepsilon_0mR))`C. `sqrt((2Qq)/(piepsilon_0mR))`D. `sqrt((Qq)/(4piepsilon_0mR))`

A charge `+Q` is uniformly distributed in a spherical volume of radius

1.	A charge `+Q` is uniformly distributed in a spherical volume of radius R. A particle of charge `+q` and mass m projected with velocity `v_0` the surface of the sherical volume to its centre inside a smooth tunnel dug across the sphere. The minimum value of `v_0` such tht it just reaches the centre (assume that thee is no resistance on the particle except electrostatic force) of he sphericle volume isA. `sqrt((Qq)/(2piepsilon_0mR))`B. `sqrt((Qq)/(piepsilon_0mR))`C. `sqrt((2Qq)/(piepsilon_0mR))`D. `sqrt((Qq)/(4piepsilon_0mR))`
Answer» Correct Answer - D `U_i+K_i=U_f+k_f` `or qV_i+1/2mv_(min)^2=qV_f+0` `=or q(1/(4piepsilon_0))(Q/R)+1/2mv_(min)^2+q[3/2xxQ/(4piepsilon_0R)]` from here we can find `v_(min)`

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