A charged oil drop is suspended in a uniform filed of `3xx10^4 v//m` so that it neither falls nor rises. The charge on the drop will be (Take the mass of the charge `=9.9xx10^-15kg` and `g=10m//s^2`)A. (a) `1.6xx10^-18C`B. (b) `3.2xx10^-18C`C. (c) `3.3xx10^-18C`D. (d) `4.8xx10^-18C`

A charged oil drop is suspended in a uniform filed of `3xx10^4 v//m` s

1.	A charged oil drop is suspended in a uniform filed of `3xx10^4 v//m` so that it neither falls nor rises. The charge on the drop will be (Take the mass of the charge `=9.9xx10^-15kg` and `g=10m//s^2`)A. (a) `1.6xx10^-18C`B. (b) `3.2xx10^-18C`C. (c) `3.3xx10^-18C`D. (d) `4.8xx10^-18C`
Answer» Correct Answer - C At equilibrium, electric force on drop balances weight of drop. `qE=mgimpliesq=(mg)/(E)=(9.9xx10^-15xx10)/(3xx10^4)=3.3xx10^(-18)C`

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A charged oil drop is suspended in a uniform filed of `3xx10^4 v//m` so that it neither falls nor rises. The charge on the drop will be (Take the mass of the charge `=9.9xx10^-15kg` and `g=10m//s^2`)A. (a) `1.6xx10^-18C`B. (b) `3.2xx10^-18C`C. (c) `3.3xx10^-18C`D. (d) `4.8xx10^-18C`

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