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A charged particle enters a uniform magnetic field with velocity vector at angle of `45^@` with the magnetic field. The pitch of the helical path followed by the particle is p. the radius of the helix will beA. `p/(sqrt(2)pi)`B. `sqrt(2)p`C. `p/(2pi)`D. `(sqrt(2)p)/(pi)` |
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Answer» Correct Answer - C `P=(2pimv cos theta)/(qB)=(2pimv)/(sqrt(2)qB)` `R=(mv sin theta)/(qB)=(mv)/(sqrt(2)qB)=p/(2pi)` |
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