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A charged particle enters into a uniform magnetic field with velocity `v_(0)` perpendicular to it , the length of magnetic field is `x=sqrt(3)/(2)R`, where `R` is the radius of the circular path of the particle in the field .The magnitude of charge in velocity of the particle when it comes out of the field is A. `2v_(0)`B. `(v_(0))/(2)`C. `(sqrt(3)v_(0))/(2)`D. `v_(0)` |
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Answer» Correct Answer - D |
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