A charged particle enters into a uniform magnetic field with velocity `v_(0)` perpendicular to it , the length of magnetic field is `x=sqrt(3)/(2)R`, where `R` is the radius of the circular path of the particle in the field .The magnitude of charge in velocity of the particle when it comes out of the field is A. `2v_(0)`B. `v_(0)//2`C. `sqrt(3)v_(0)//2`D. `v_(0)`

A charged particle enters into a uniform magnetic field with velocity

1.	A charged particle enters into a uniform magnetic field with velocity `v_(0)` perpendicular to it , the length of magnetic field is `x=sqrt(3)/(2)R`, where `R` is the radius of the circular path of the particle in the field .The magnitude of charge in velocity of the particle when it comes out of the field is A. `2v_(0)`B. `v_(0)//2`C. `sqrt(3)v_(0)//2`D. `v_(0)`
Answer» Correct Answer - D `sin theta=(d)/(R)=(sqrt(3))/(2)impliestheta=60^(@)` `vec(v)_(f)=v cos hat(t)+v sin thetahat(j),vec(v)_(i)=vhat(i)`

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