InterviewSolution
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InterviewSolution
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A charged particle goes undeflected in a region containing electric and magnetic field. It is possible that (i) `vec(E) || vec(B). vec(v) || vec(E)` (ii) `vec(E)` is not parallel to `vec(B)` (iii) `vec(v) || vec(B)` but `vec(E)` is not parallel to `vec(B)` (iv) `vec(E)||vec(B)` but `vec(v)` is not parallel to `vec(E)`A. `vec(E)||vec(B),vec(v)||vec(E)`B. `vec(E)` is not parallel to `vec(B)`C. `vec(v)||vec(B)` but `vec(E)` is not parallel to `vec(E)`D. `vec(E)||vec(B)` but `vec(v)` is not parallel to `vec(E)`. |
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Answer» Correct Answer - A,B,C,D If `B & E & v` are in same direction then particle will be undeflected cause `vec(F_(M))=0` `(b)` is also possible is not parallel to `vec(B)` If `vec(F_(M))=qvB` and `vec(F_(E))=qE` then v is `_|_` to `vec(E)` and v is `_|_` to `vec(B) vec(E)` is not parallel to `vec(B)` |
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