A charged particle having a charge of `-2.0 xx 10^(-6) C` is placed close to a non-conducting plate having a surface charge density `4.0 xx 10^(-6) C m^(-2)`. Find the force of attraction between the particle and the plate.

A charged particle having a charge of `-2.0 xx 10^(-6) C` is placed cl

1.	A charged particle having a charge of `-2.0 xx 10^(-6) C` is placed close to a non-conducting plate having a surface charge density `4.0 xx 10^(-6) C m^(-2)`. Find the force of attraction between the particle and the plate.
Answer» Correct Answer - `0.45 N` Here, `q = -2xx10^(-6) C, sigma = 4xx10^(-6) Cm^(-2)` Field of attraction between the charged particle and the plate, `F = qE = (sigma q)/(2 in_(0)) = (4xx10^(-6) xx2xx10^(-6))/(2xx8.845xx10^(-12))` `= 0.45 N`

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A charged particle having a charge of `-2.0 xx 10^(-6) C` is placed close to a non-conducting plate having a surface charge density `4.0 xx 10^(-6) C m^(-2)`. Find the force of attraction between the particle and the plate.

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