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A charged particle moves in a uniform magnetic field `B=(2hati-3hatj)` TA. if velocity of the particles is `(6hatK)m//s`, particle moves in a circleB. if velocity of the particle is `(-4hati+6hatj)m//s`, particle moves in a straight meC. if velocity of the particle is `(hati+2hatj)m//s`, particle moves in a helical pathD. In all the above three cases speed of the particle remains unchanged |
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Answer» Correct Answer - all |
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