A charged particle moving with a velocity \(\vec v\) enters a region of uniform magnetic field \(\vec B\) such that the pitch of the resulting helical motion is equal to the radius of the helix. The angle between \(\vec v\) and \(\vec B\) is(A) tan-1 2π (B) sin-1 2π (C) tan-1 \(\cfrac1{2\pi}\left(\cfrac{qB}{m}\right)^2\)(D) tan-1 2π2π\(\left(\cfrac{qB}{m}\right)^2\)

A charged particle moving with a velocity \(\vec v\) enters a region

1.	A charged particle moving with a velocity \(\vec v\) enters a region of uniform magnetic field \(\vec B\) such that the pitch of the resulting helical motion is equal to the radius of the helix. The angle between \(\vec v\) and \(\vec B\) is(A) tan-1 2π (B) sin-1 2π (C) tan-1 \(\cfrac1{2\pi}\left(\cfrac{qB}{m}\right)^2\)(D) tan-1 2π2π\(\left(\cfrac{qB}{m}\right)^2\)
Answer» Correct option is (A) tan^-1 2π