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A charged particle of charge 1 mC and mass 2g is moving with a speed of 5m/s in a uniform magnetic field of 0.5 tesla. Find the maximum acceleration of the charged particle

Answer» `m = 2 xx 10^(-3) kg, v = 5 m//s, B = 0.5` testa, `q = 1 xx 10^(-3) C`
`vec(F) = q(vec(v) xx vec(B))`
`rArr F = qvB sin theta`
`rArr F = 10^(-3) xx 5 xx 0.5 xx sin 90^(@) N`
`rArr F = 2.5 xx 10^(-3) N`
`a = (F)/(m)`
`rArr a = (2.5 xx 10^(-3))/(2 xx 10^(-3)) N//kg`
`rArr a = 1.25 m//s^(2)`


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