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A charged particle of mass m = 2 kg and charge `1 muC` is projected from a horizontal ground at an angle `theta=45^@` with speed `10ms^(-1)`. In space, a horizontal electric field towards the direction of projection `E = 2 xx 10^(7) NC^(-1)` exists. The range of the projectile isA. 20 mB. 60 mC. 200 mD. 180 m |
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Answer» Correct Answer - A `a_(x)=(qE)/(m)=(10^(-4)xx2xx10^(7))/(2)=10ms^(-2)` Tune of flight `=(2usintheta)/(g)=(2xx10xx(1)/(sqrt(2)))/(10)=sqrt(2)s` Hence `R=u_(x)T+(1)/(2)a_(x)T^(2)` `=10cos45^(@)xxT+(1)/(2)a_(x)T^(2)` `=(10)/(sqrt(2))xxsqrt(2)+(1)/(2)xx10xx2` `=20m`. |
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