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A charged particle of mass m and charge e is released from rest in an electric field E. If kinetic energy of particle after time t is `E_k` and linear momentum is p, thenA. `p=Eet`B. `p=2eEt`C. `E_K=(e^2E^2t^2)/(2m)`D. `E_K=(e^2E^2t^2)/(m)` |
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Answer» Correct Answer - A::C (a) As `v=u+at`, `u=0` `v=at` As `a=(eE)/(m)` `:. v=(eEt)/(m)` and `p=mv` so `p=(meEt)/(m)=eEt` (c) `E_k=(P^2)/(2m)=(e^2E^2t^2)/(2m)` |
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