InterviewSolution
Saved Bookmarks
| 1. |
A charged particle of mass m and charge q, a uniform magneric field B acting into the plane. The plane is frictional having coefficient of friction `mu`. The speed of charged particle just before entering into the region is `V_(0)`. The radius of curvature of the path after the time `(v_(0))/(2mug)` isA. `(mv_(0))/(qB)`B. `(mv_(0))/(2qB)`C. `(mv_(0))/(4qB)`D. None of these |
|
Answer» Correct Answer - b Here, centripetal acceleration is provided by magnetic force but tangential acceleration is provided by force of friction `(mv^(2))/r=qvB` `:. r=(mv)/(qB)` Tangential acceleration `=a=(-mumg)/m` `v=-mug((v_(0))/(2mug)) =(v_(0))/2` `:. r=(mv)/(qB)=(mv_(0))/(2qB)` |
|