A charged particle of specific charge, α=(qm) is released at origin at t=0 with velocity v=v0(^i+^j) in a uniform magnetic field B=B0^i. Coordinates of particle at time t=πB0α are:

A charged particle of specific charge, α=(qm) is released at origin a

1.	A charged particle of specific charge, α=(qm) is released at origin at t=0 with velocity v=v0(^i+^j) in a uniform magnetic field B=B0^i. Coordinates of particle at time t=πB0α are:
Answer» A charged particle of specific charge, $α = (\frac{q}{m})$ is released at origin at $t = 0$ with velocity $v = v_{0} (^i +^j)$ in a uniform magnetic field $B = B_{0}^i$ . Coordinates of particle at time $t = \frac{π}{B_{0} α}$ are:

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A charged particle of specific charge, α=(qm) is released at origin at t=0 with velocity v=v0(^i+^j) in a uniform magnetic field B=B0^i. Coordinates of particle at time t=πB0α are:

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